(x^2-2x)(2x-2)-9(2x-2)/(x^2-2x)=0

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Solution for (x^2-2x)(2x-2)-9(2x-2)/(x^2-2x)=0 equation: 



(x^2-2x)(2x-2)-9(2x-2)/(x^2-2x)=0



Domain of the equation: (x^2-2x)!=0

x∈R



We multiply all the terms by the denominator


((x^2-2x)(2x-2))*(x^2-2x)-9(2x-2)=0



We calculate terms in parentheses: +((x^2-2x)(2x-2))*(x^2-2x), so:

(x^2-2x)(2x-2))*(x^2-2x

We add all the numbers together, and all the variables

-2x+(x^2-2x)(2x-2))*(x^2

Back to the equation:

+(-2x+(x^2-2x)(2x-2))*(x^2)



We multiply parentheses

(-2x+(x^2-2x)(2x-2))*x^2-18x+18=0

We add all the numbers together, and all the variables

-18x+(-2x+(x^2-2x)(2x-2))*x^2+18=0

We move all terms containing x to the left, all other terms to the right

-18x+(-2x+(x^2-2x)(2x-2))*x^2=-18

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